Electric power calculation of air conditioning equ

2022-09-19
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Calculation of the electric power of the negative processing temperature of the air-conditioning equipment in the house without decomposing the load

Abstract: the air-conditioning and toilet ventilation in the house belong to the lighting load, although many motors in the air-conditioning equipment are running. The power load level of air conditioning belongs to level III. In many cases, engineers and technicians engaged in electrical design need to estimate the electrical load of indoor air conditioning. This is the ability that an experienced electrical engineer should have. This requires some basic technical information

key words: residential air conditioning equipment load electric power Untitled Document air conditioning and toilet ventilation are lighting loads, although many motors in air conditioning equipment are running. The power load level of air conditioning belongs to level III. Estimation of cooling and heating load index of a residence in many cases, engineers and technicians engaged in electrical design need to estimate the electrical load of indoor air conditioning. This is the ability that an experienced electrical engineer should have. This requires some basic technical information. There are many factors that affect indoor cooling load consumption, including heat dissipation of human body, absorption and outward conduction of buildings, heating of lighting fixtures, absorption of fresh air and removal of outdoor air to take away cooling capacity. Estimated index number of air conditioning cooling load in some places room type indoor number of people/m2 building load w/m2 human load w/m2 lighting load w/m2 fresh air volume m3/person H fresh air load w/m2 total load w/m2 kcal/m2 1 apartment residence 0.10 70.00 14.00 20.00 50.00 54.00 158.00 135.88 2 bedrooms 0.25 50.00 41.00 50.00 25.00 67.00 208.00 178.88 3 ordinary rooms 0.10 50.00 14.00 20.00 25.00 36.00 145.00 124.70 4 guest rooms 0.06 60.00 7.00 20.00 50.00 40.00 177.00 152.22 5 dining room living room 0.50 35.00 70.00 20.00 40.00 190.00 163.40 6 bar 0.50 35.00 70.00 15.00 25.00 136.00 256 00 220.16 7 Cafe 0.50 35.00 70.00 15.00 25.00 136.00 256.00 220.16 8 snack bar 0.20 40.00 31.00 40.00 20.00 50.00 181.00 156.66 9 store 0.20 40.00 31.00 40.00 20.00 50.00 181.00 156.66 10 small personal office 0.10 40.00 14.00 50.00 25.00 40.00 145.00 124.70 11 general office 0.20 40.00 28.00 40.00 25.00 45.00 178.78 12 book reading 0.20 50.00 28.00 30.00 25.00 60.00 193.00 166.00 13 conference room 0.64 60.00 89.00 40.00 25.00 136.00 350.00 301.00 14 shopping mall 1.00 35.00 140.00 40.00 12.00 136.00 spectral analysis method is the 347.00 298.00 two equivalent calculation based on the characteristic that the material atom can emit a characteristic spectrum under certain conditions. 1 Unit of cooling capacity: the units of cooling capacity (i.e. heat) include Joule (J), kilojoule (kJ), Watt (W) and kilowatt (kw); Calorie, kilocalorie (kcal) (kcal) the heat required to heat a kilogram of water from 19.56 ℃ to 20.5 ℃ at standard atmospheric pressure is defined as kilocalorie (kcal). That is 1kcal/kg ℃ or approximately equal to 1kcal/m3 ℃ 2 Conversion of units of cooling capacity (i.e. heat): 1w=1j/s=0.238844cal/s1wh (electric heating) = 0.86cal3 Electric heating equivalent 1kwh = 860cal efficiency ratio of three refrigerators refrigeration efficiency ratio η= Refrigerating capacity of refrigerator/heating efficiency ratio of input electric power of refrigerator η= Heating capacity of heating device/input electric power of heating device 1 The villa central air conditioner fwr-20b1 has a nominal refrigerating capacity of 20.10kw and an input power of 7.0kw; The nominal heating capacity is 21.80kw and the input power is 6.40kw. Compressor input power 2x2.80kw; Air side heat exchanger 2x0.19kw; Water side heat exchanger 1x0.90kw. Calculate the refrigeration and heating efficiency ratio of the air conditioner. Known: nominal refrigerating capacity 20.10kw, total input power 7.00kw; The nominal heating capacity is 21.80kw, and the total input electric power is 6.40kw. Efficiency ratio of refrigerator η= 20.10/7.0 = 2.87 efficiency ratio of heating device η= 21.80/6.4=3.412. Villa central air conditioner sa-08csh, with a nominal refrigerating capacity of 22400kcal/h; The nominal photoelectric encoder will have pulse signal output, and the heating capacity is 25800kcal/h; The refrigerating power of the compressor is 9.90kw; Heating power is 9.50kw; Cooling fan: 0.90kw; Cold water pump 1.00kw. Calculate the refrigeration and heating efficiency ratio of the air conditioner. (1) Convert the cold and heat from kilocalorie to electric heat. It is known that 1kW (electric heating) = 8604, the number of experimental fixtures used in special industries increases kcal/h1) refrigerating capacity = 22400kcal/h/860kcal/h=26.05kw2) heating capacity = 25800kcal/h/860

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